What is the derivative of f(x)=tan(sqrt(x+1)) ?

The derivative of f(x)=tan(sqrt(x+1)) is (sec^2(sqrt(x+1)))/(2sqrt(x+1))

What is the first derivative of f(x)=tan(sqrt(x+1)) ?

The first derivative of f(x)=tan(sqrt(x+1)) is (sec^2(sqrt(x+1)))/(2sqrt(x+1))

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derivative of

f (x) = tan (x + 1)

\frac{sec ^{2} ( x + 1 )}{2 x + 1}

Solution steps

\frac{d}{d x} (tan (x + 1))

Apply the chain rule:

sec^{2} (x + 1) \frac{d}{d x} (x + 1)

= sec^{2} (x + 1) \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = \frac{1}{2 x + 1}

= sec^{2} (x + 1) \frac{1}{2 x + 1}

Simplify

sec^{2} (x + 1) \frac{1}{2 x + 1} : \frac{sec ^{2} ( x + 1 )}{2 x + 1}

= \frac{sec ^{2} ( x + 1 )}{2 x + 1}

y^{^{'}} = 0.1 - \frac{y}{400}

\int \frac{1}{2 + sin ( x ) + cos ( x )} d x

\int r e^{r^{2}} d r

sin (5 x + 6 y) = x y

\frac{d ^{2} y}{d x ^{2}} = 9 y

What is the derivative of f(x)=tan(sqrt(x+1)) ?
The derivative of f(x)=tan(sqrt(x+1)) is (sec^2(sqrt(x+1)))/(2sqrt(x+1))
What is the first derivative of f(x)=tan(sqrt(x+1)) ?
The first derivative of f(x)=tan(sqrt(x+1)) is (sec^2(sqrt(x+1)))/(2sqrt(x+1))