What is the derivative of 3x^2+6x-9 ?

The derivative of 3x^2+6x-9 is 6x+6

What is the first derivative of 3x^2+6x-9 ?

The first derivative of 3x^2+6x-9 is 6x+6

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\frac{d}{d x} (3 x^{2} + 6 x - 9)

6 x + 6

Solution steps

\frac{d}{d x} (3 x^{2} + 6 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (9) = 0

= 6 x + 6 - 0

Simplify

= 6 x + 6

f (x) = (x + 2 x)

x (2 x + 3)^{5}

\int (x^{2} + 3 x) cos (x) d x

\frac{d}{d x} (x^{- 3} + \frac{1}{x ^{7}})

\frac{2}{x - 1}

What is the derivative of 3x^2+6x-9 ?
The derivative of 3x^2+6x-9 is 6x+6
What is the first derivative of 3x^2+6x-9 ?
The first derivative of 3x^2+6x-9 is 6x+6