What is the derivative of 2/(x-1) ?

The derivative of 2/(x-1) is -2/((x-1)^2)

What is the first derivative of 2/(x-1) ?

The first derivative of 2/(x-1) is -2/((x-1)^2)

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derivative of

\frac{2}{x - 1}

- \frac{2}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 1 ) ^{2}} \frac{d}{d x} (x - 1)

= - \frac{1}{( x - 1 ) ^{2}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 2 (- \frac{1}{( x - 1 ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( x - 1 ) ^{2}} \cdot 1) : - \frac{2}{( x - 1 ) ^{2}}

= - \frac{2}{( x - 1 ) ^{2}}

\int \frac{x + 1}{2 x - x ^{2}} d x

\frac{d}{d x} (x^{4} y^{2})

\frac{d}{d x} (\frac{2 x ^{2} + 1}{x})

\int 6 e^{4 t a n (2 x)} sec^{2} (2 x) d x

\frac{d}{d x} (\frac{- x ^{2}}{y ^{2}})

What is the derivative of 2/(x-1) ?
The derivative of 2/(x-1) is -2/((x-1)^2)
What is the first derivative of 2/(x-1) ?
The first derivative of 2/(x-1) is -2/((x-1)^2)