What is the d/(dy)(10-6y+e^{-3x}) ?

The d/(dy)(10-6y+e^{-3x}) is -6

What is the first d/(dy)(10-6y+e^{-3x}) ?

The first d/(dy)(10-6y+e^{-3x}) is -6

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\frac{d}{d y} (10 - 6 y + e^{- 3 x})

- 6

Solution steps

\frac{d}{d y} (10 - 6 y + e^{- 3 x})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (10) - \frac{d}{d y} (6 y) + \frac{d}{d y} (e^{- 3 x})

\frac{d}{d y} (10) = 0

\frac{d}{d y} (6 y) = 6

\frac{d}{d y} (e^{- 3 x}) = 0

= 0 - 6 + 0

Simplify

= - 6

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