What is the derivative of-x+1/x+1 ?

The derivative of-x+1/x+1 is -1/(x^2)-1

What is the first derivative of-x+1/x+1 ?

The first derivative of-x+1/x+1 is -1/(x^2)-1

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\frac{d}{d x} (- x + \frac{1}{x} + 1)

- \frac{1}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (- x + \frac{1}{x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (\frac{1}{x}) + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (1) = 0

= - 1 - \frac{1}{x ^{2}} + 0

Simplify

= - \frac{1}{x ^{2}} - 1

\frac{d}{d x} (\frac{16}{x ( 4 - x ^{2} )})

\int_{2}^{t} \frac{1}{5 x ^{5}} d x

\int \frac{1}{7 + 6 x - x ^{2}} d x

n = 1 \sum \infty (sin (1))^{n}

\int - 3 x d x

What is the derivative of-x+1/x+1 ?
The derivative of-x+1/x+1 is -1/(x^2)-1
What is the first derivative of-x+1/x+1 ?
The first derivative of-x+1/x+1 is -1/(x^2)-1