What is the derivative of x+(400/x) ?

The derivative of x+(400/x) is 1-(400)/(x^2)

What is the first derivative of x+(400/x) ?

The first derivative of x+(400/x) is 1-(400)/(x^2)

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\frac{d}{d x} (x + \frac{400}{x})

1 - \frac{400}{x ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{400}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{400}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{400}{x}) = - \frac{400}{x ^{2}}

= 1 - \frac{400}{x ^{2}}

\frac{5 s + 5.1}{s ^{2} + s + 20}

\frac{\partial}{\partial x} (x^{2} sin (10 t))

\int \frac{1}{( 5 + x ^{2} ) ^{\frac{3}{2}}} d x

\int x e^{θ x} d x

\frac{x + 1}{x ^{3} + x - 4}

What is the derivative of x+(400/x) ?
The derivative of x+(400/x) is 1-(400)/(x^2)
What is the first derivative of x+(400/x) ?
The first derivative of x+(400/x) is 1-(400)/(x^2)