What is the derivative of x^4-1 ?

The derivative of x^4-1 is 4x^3

What is the first derivative of x^4-1 ?

The first derivative of x^4-1 is 4x^3

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\frac{d}{d x} (x^{4} - 1)

4 x^{3}

Solution steps

\frac{d}{d x} (x^{4} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (1) = 0

= 4 x^{3} - 0

Simplify

= 4 x^{3}

\int sec (θ) d θ

\int x arctan (18 x) d x

\int t sec^{2} (6 t) d t

n = 0 \sum \infty \frac{1}{1. 1 ^{n}}

\frac{d}{d x} (x^{4} + 8 x^{3} + 6 x^{2} - 40 x + 25)