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Popular >

integral from 0 to 4 of 2x-x^2

Solution

\int_{0}^{4} 2 x - x^{2} d x

Solution

- \frac{16}{3}

+1

Decimal

- 5.33333 \dots

Solution steps

\int_{0}^{4} 2 x - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x - \int_{0}^{4} x^{2} d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} x^{2} d x = \frac{64}{3}

= 16 - \frac{64}{3}

Simplify

16 - \frac{64}{3} : - \frac{16}{3}

= - \frac{16}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 2x-x^2 ?
The integral from 0 to 4 of 2x-x^2 is -16/3