What is the limit as x approaches 1 of |x-4|+2 ?

The limit as x approaches 1 of |x-4|+2 is 5

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limit as x approaches 1 of |x-4|+2

x \to 1 lim (∣ x - 4 ∣ + 2)

5

Solution steps

x \to 1 lim (∣ x - 4 ∣ + 2)

Plug in the value

x = 1

= ∣ 1 - 4 ∣ + 2

Simplify

∣ 1 - 4 ∣ + 2 : 5

= 5

π r^{2}

\frac{\partial}{\partial u} (\frac{u - v}{3})

x \to - 2 - lim (2 x)

x y^{^{'}} - 3 y + 24 = 0

\frac{d ^{2}}{d x ^{2}} (1 0^{x})

What is the limit as x approaches 1 of |x-4|+2 ?
The limit as x approaches 1 of |x-4|+2 is 5