What is the tangent of 3x^2,\at x=4 ?

The tangent of 3x^2,\at x=4 is y=24x-48

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tangent of 3x^2,\at x=4

tangent of

3 x^{2}, at x = 4

y = 24 x - 48

Solution steps

Find the tangent point:

(4, 48)

Find the slope of

y = 3 x^{2} : \frac{d y}{d x} = 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 24

Find the line with slope m=

24

and passing through

(4, 48) : y = 24 x - 48

y = 24 x - 48

x \to 5 lim (x)

t \to + 0 lim (\frac{8}{t} - \frac{8}{t ^{2} + t})

\int 6 x d x

\int (x^{2} + 3) sin (2 x) d x

- e^{- x} x + 3 e^{- x}