What is the limit as x approaches 3 of (x^3-9)/(x-3) ?

The limit as x approaches 3 of (x^3-9)/(x-3) is diverges

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limit as x approaches 3 of (x^3-9)/(x-3)

x \to 3 lim (\frac{x ^{3} - 9}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{x ^{3} - 9}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{3} - 9}{x - 3}) = \infty

x \to 3 - lim (\frac{x ^{3} - 9}{x - 3}) = - \infty

= diverges

x^{3} + 2 x + 1, 1

\int \frac{x ^{7}}{7} - \frac{4 x ^{5}}{5} + \frac{x ^{2}}{2} + x + C d x

(8 (2 x)^{4} + 5)^{3}

\int_{1}^{3} \frac{d}{d t} (2 t^{3} + 3 t - 1) d t

\frac{\partial}{\partial x} ((x^{p} + y^{p})^{\frac{1}{p}})

What is the limit as x approaches 3 of (x^3-9)/(x-3) ?
The limit as x approaches 3 of (x^3-9)/(x-3) is diverges