What is the derivative of 5sec(8x) ?

The derivative of 5sec(8x) is 40sec(8x)tan(8x)

What is the first derivative of 5sec(8x) ?

The first derivative of 5sec(8x) is 40sec(8x)tan(8x)

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derivative of

5 sec (8 x)

40 sec (8 x) tan (8 x)

Solution steps

\frac{d}{d x} (5 sec (8 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sec (8 x))

Apply the chain rule:

sec (8 x) tan (8 x) \frac{d}{d x} (8 x)

= sec (8 x) tan (8 x) \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= 5 sec (8 x) tan (8 x) \cdot 8

Simplify

= 40 sec (8 x) tan (8 x)

\frac{\partial}{\partial x} (2 y^{2} sin (x y))

t \to 0 lim (t ln (t))

\frac{d}{d x} (90 + 45 cos (\frac{x ^{2}}{18}))

\frac{\partial}{\partial y} (5 x e^{x^{2}} + y^{2})

x \to 0 lim (\frac{x ^{2} - 2 x}{x})

What is the derivative of 5sec(8x) ?
The derivative of 5sec(8x) is 40sec(8x)tan(8x)
What is the first derivative of 5sec(8x) ?
The first derivative of 5sec(8x) is 40sec(8x)tan(8x)