What is the first derivative of 3x^2-4 ?

The first derivative of 3x^2-4 is 6x

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derivative of 3x^2-4

\frac{d}{d x} (3 x^{2} - 4)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= 6 x - 0

Simplify

= 6 x

arctan (\frac{1}{x})

\frac{\partial}{\partial v} (sin (v))

\frac{1}{x + 4}, 0

(x, y, z) \to (π, 0, \frac{1}{3}) lim (e^{y^{2}} tan (x z))

\int sec^{2} (4 x) d x