What is the derivative of 4x^2-3x ?

The derivative of 4x^2-3x is 8x-3

What is the first derivative of 4x^2-3x ?

The first derivative of 4x^2-3x is 8x-3

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\frac{d}{d x} (4 x^{2} - 3 x)

8 x - 3

Solution steps

\frac{d}{d x} (4 x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

= 8 x - 3

\int 21 - x^{2} - 4 x d x

\frac{d}{d x} (2 x^{2} + 4 x y - x - 2 y)

y^{^{''}} - 8 y^{^{'}} + 8 y = 0

\int (x^{2} + 6) \cdot e^{- x} d x

\int x^{2} cos (m x) d x

What is the derivative of 4x^2-3x ?
The derivative of 4x^2-3x is 8x-3
What is the first derivative of 4x^2-3x ?
The first derivative of 4x^2-3x is 8x-3