What is the first derivative of 8x+1 ?

The first derivative of 8x+1 is 8

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derivative of 8x+1

\frac{d}{d x} (8 x + 1)

8

Solution steps

\frac{d}{d x} (8 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (1)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (1) = 0

= 8 + 0

Simplify

= 8

\int (x^{2} + 7) d x

\frac{d}{d x} (arctan (\frac{2 x}{1 - x ^{2}}))

\frac{\partial}{\partial x} ((2 x + 3 x y^{2})^{2})

y = x^{2} + 3 x + 1, y = - x + 1

\frac{d y}{d x} = \frac{x}{( 1 + 2 y )}