What is the derivative of y=ln(x^3) ?

The derivative of y=ln(x^3) is 3/x

What is the first derivative of y=ln(x^3) ?

The first derivative of y=ln(x^3) is 3/x

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derivative of

y = ln (x^{3})

\frac{3}{x}

Solution steps

\frac{d}{d x} (ln (x^{3}))

Apply the chain rule:

\frac{1}{x ^{3}} \frac{d}{d x} (x^{3})

= \frac{1}{x ^{3}} \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{1}{x ^{3}} \cdot 3 x^{2}

Simplify

\frac{1}{x ^{3}} \cdot 3 x^{2} : \frac{3}{x}

= \frac{3}{x}

\int 3 x^{- 3} d x

\int ln (5 x^{3}) d x

(- 4, 3), (- 2, 2)

\int_{1}^{e} 2 t^{2} ln (t) d t

u^{3}

What is the derivative of y=ln(x^3) ?
The derivative of y=ln(x^3) is 3/x
What is the first derivative of y=ln(x^3) ?
The first derivative of y=ln(x^3) is 3/x