What is the integral of (1/((1+x)^2)) ?

The integral of (1/((1+x)^2)) is -1/(1+x)+C

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integral of (1/((1+x)^2))

\int (\frac{1}{( 1 + x ) ^{2}}) d x

- \frac{1}{1 + x} + C

Solution steps

\int \frac{1}{( 1 + x ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = 1 + x

= - \frac{1}{1 + x}

Add a constant to the solution

= - \frac{1}{1 + x} + C

\int_{1}^{\infty} x e^{- 3 x} d x

\frac{d}{d x} (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2})

\frac{d y}{d x} = x (6 - y)

\frac{d}{d x} (\frac{2 x}{1 + 5 x ^{2}})

x y^{^{'}} + 2 y = 4 x

What is the integral of (1/((1+x)^2)) ?
The integral of (1/((1+x)^2)) is -1/(1+x)+C