What is the solution for (dy)/(dx)=9x+y,y(0)=9 ?

The solution for (dy)/(dx)=9x+y,y(0)=9 is y=-9(x+1)+18e^x

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(dy)/(dx)=9x+y,y(0)=9

\frac{d y}{d x} = 9 x + y, y (0) = 9

y = - 9 (x + 1) + 18 e^{x}

Solution steps

\frac{d y}{d x} = 9 x + y

Solve linear ODE:

y = - 9 (x + 1) + 18 e^{x}

y = - 9 (x + 1) + 18 e^{x}

6 tan (x), at x = \frac{π}{3}

y = \frac{6 x ^{2} + 8 x + 8}{x}

\frac{\partial}{\partial x} (x + 4 y)

\int \frac{- 2 x - 4}{x ^{3} + x ^{2} + x} d x

\frac{\partial}{\partial y} (tan (\frac{x}{y}))

What is the solution for (dy)/(dx)=9x+y,y(0)=9 ?
The solution for (dy)/(dx)=9x+y,y(0)=9 is y=-9(x+1)+18e^x