What is the integral of x(x+3)^3 ?

The integral of x(x+3)^3 is (x^5)/5+(9x^4)/4+9x^3+(27x^2)/2+C

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integral of x(x+3)^3

\int x (x + 3)^{3} d x

\frac{x ^{5}}{5} + \frac{9 x ^{4}}{4} + 9 x^{3} + \frac{27 x ^{2}}{2} + C

Solution steps

\int x (x + 3)^{3} d x

Expand

x (x + 3)^{3} : x^{4} + 9 x^{3} + 27 x^{2} + 27 x

= \int x^{4} + 9 x^{3} + 27 x^{2} + 27 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{4} d x + \int 9 x^{3} d x + \int 27 x^{2} d x + \int 27 x d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 9 x^{3} d x = \frac{9 x ^{4}}{4}

\int 27 x^{2} d x = 9 x^{3}

\int 27 x d x = \frac{27 x ^{2}}{2}

= \frac{x ^{5}}{5} + \frac{9 x ^{4}}{4} + 9 x^{3} + \frac{27 x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{5}}{5} + \frac{9 x ^{4}}{4} + 9 x^{3} + \frac{27 x ^{2}}{2} + C

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What is the integral of x(x+3)^3 ?
The integral of x(x+3)^3 is (x^5)/5+(9x^4)/4+9x^3+(27x^2)/2+C