What is the derivative of 2sec(x+tan(x)) ?

The derivative of 2sec(x+tan(x)) is 2sec(x)tan(x)+sec^2(x)

What is the first derivative of 2sec(x+tan(x)) ?

The first derivative of 2sec(x+tan(x)) is 2sec(x)tan(x)+sec^2(x)

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\frac{d}{d x} (2 sec (x) + tan (x))

2 sec (x) tan (x) + sec^{2} (x)

Solution steps

\frac{d}{d x} (2 sec (x) + tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sec (x)) + \frac{d}{d x} (tan (x))

\frac{d}{d x} (2 sec (x)) = 2 sec (x) tan (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 2 sec (x) tan (x) + sec^{2} (x)

(2 x y - 3 x^{2}) d x + x^{2} d y = 0

f (x) = ln (cos (3 x))

\frac{\partial}{\partial x} (x^{3} e 3 x y)

\frac{d}{d x} (y^{2} cos (x))

\frac{\partial}{\partial x} (25 + x^{2})

What is the derivative of 2sec(x+tan(x)) ?
The derivative of 2sec(x+tan(x)) is 2sec(x)tan(x)+sec^2(x)
What is the first derivative of 2sec(x+tan(x)) ?
The first derivative of 2sec(x+tan(x)) is 2sec(x)tan(x)+sec^2(x)