What is the limit as x approaches-1+of 2x^2-4x+2 ?

The limit as x approaches-1+of 2x^2-4x+2 is 8

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limit as x approaches-1+of 2x^2-4x+2

x \to - 1 + lim (2 x^{2} - 4 x + 2)

8

Solution steps

x \to - 1 + lim (2 x^{2} - 4 x + 2)

Plug in the value

x = - 1

= 2 (- 1)^{2} - 4 (- 1) + 2

Simplify

2 (- 1)^{2} - 4 (- 1) + 2 : 8

= 8

x \to 1 lim (x - 1)

\int x^{4} (5 x^{5} + 9)^{7} d x

y = \frac{tan ( x )}{1 - sec ( x )}

\frac{\partial}{\partial x} (8 x y e^{x z})

\frac{d}{d x} (e^{\frac{1}{x}} x^{2} - 1)

What is the limit as x approaches-1+of 2x^2-4x+2 ?
The limit as x approaches-1+of 2x^2-4x+2 is 8