What is the derivative of (3x-8)/(7x+4) ?

The derivative of (3x-8)/(7x+4) is (68)/((7x+4)^2)

What is the first derivative of (3x-8)/(7x+4) ?

The first derivative of (3x-8)/(7x+4) is (68)/((7x+4)^2)

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derivative of

\frac{3 x - 8}{7 x + 4}

\frac{68}{( 7 x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x - 8}{7 x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - 8 ) ( 7 x + 4 ) - \frac{d}{d x} ( 7 x + 4 ) ( 3 x - 8 )}{( 7 x + 4 ) ^{2}}

\frac{d}{d x} (3 x - 8) = 3

\frac{d}{d x} (7 x + 4) = 7

= \frac{3 ( 7 x + 4 ) - 7 ( 3 x - 8 )}{( 7 x + 4 ) ^{2}}

Expand

3 (7 x + 4) - 7 (3 x - 8) : 68

= \frac{68}{( 7 x + 4 ) ^{2}}

y^{^{'}} - \frac{4}{x} y = \frac{y ^{3}}{x ^{5}}, y (1) = 1

(1.1) (2.5)

n = 1 \sum \infty \frac{3 e ^{n}}{n ^{5}}

\frac{\partial}{\partial x} ((1 - 3 x y) e^{- x y})

\int (5^{x} - sec^{2} (x)) d x

What is the derivative of (3x-8)/(7x+4) ?
The derivative of (3x-8)/(7x+4) is (68)/((7x+4)^2)
What is the first derivative of (3x-8)/(7x+4) ?
The first derivative of (3x-8)/(7x+4) is (68)/((7x+4)^2)