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Popular >

y^{''}+4y^'=0

Solution

y^{^{''}} + 4 y^{^{'}} = 0

Solution

y = c_{1} + c_{2} e^{- 4 t}

Solution steps

y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 t}

y = c_{1} + c_{2} e^{- 4 t}

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y^'=0 ?
The solution for y^{''}+4y^'=0 is y=c_{1}+c_{2}e^{-4t}