What is area-x^2+5,x^2-10x+17,2,3 ?

The answer to area-x^2+5,x^2-10x+17,2,3 is 1/3

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area-x^2+5,x^2-10x+17,2,3

area

- x^{2} + 5, x^{2} - 10 x + 17, 2, 3

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

Apply the area formula:

\int_{2}^{3} - x^{2} + 5 - (x^{2} - 10 x + 17) d x

Solve

\int_{2}^{3} - x^{2} + 5 - (x^{2} - 10 x + 17) d x : \frac{1}{3}

The area is:

= \frac{1}{3}

f (x) = \frac{1}{( x ^{6} - \frac{7}{x} ) ^{2}}

- \frac{4}{( 4 x - 17 ) ^{\frac{3}{2}}}

\frac{\partial}{\partial x} (ln (4 x + y))

n = 0 \sum \infty e^{- 2 nab}

n = 1 \sum \infty \frac{1}{3 n + 5}

What is area-x^2+5,x^2-10x+17,2,3 ?
The answer to area-x^2+5,x^2-10x+17,2,3 is 1/3