What is the tangent of x^2+1 ?

The tangent of x^2+1 is y=2a_{0}x-a_{0}^2+1

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tangent of x^2+1

tangent of

x^{2} + 1

y = 2 a_{0} x - a_{0}^{2} + 1

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} + 1)

Find the slope of

y = x^{2} + 1 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} + 1) : y = 2 a_{0} x - a_{0}^{2} + 1

y = 2 a_{0} x - a_{0}^{2} + 1

n = 5 \sum \infty \frac{1}{n + 25}

\frac{d}{d t} (\frac{6}{t})

y^{^{'}} = 3 x (x + 2)^{3}

y^{^{'}} = k y (4000 - y), y (0) = 150

\frac{\partial}{\partial x} (4 x arctan (\frac{y}{z}))