What is the tangent of 2\sqrt[3]{x},\at x=1 ?

The tangent of 2\sqrt[3]{x},\at x=1 is y= 2/3 x+4/3

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tangent of 2\sqrt[3]{x},\at x=1

tangent of

2 3 x, at x = 1

y = \frac{2}{3} x + \frac{4}{3}

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

y = 2 3 x : \frac{d y}{d x} = \frac{2}{3 x ^{\frac{2}{3}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(1, 2) : y = \frac{2}{3} x + \frac{4}{3}

y = \frac{2}{3} x + \frac{4}{3}

\int_{0}^{1} x^{- \frac{1}{2}} d x

\frac{\partial}{\partial x} (\frac{x + 5}{y + 5})

f (θ) = e^{t a n (θ)}

\frac{d}{d x} (2 e^{x} + \frac{8}{3 x})

\frac{d y}{d x} - x y = 1

What is the tangent of 2\sqrt[3]{x},\at x=1 ?
The tangent of 2\sqrt[3]{x},\at x=1 is y= 2/3 x+4/3