What is the derivative of g(x)=x^3-6x^2+9x+3 ?

The derivative of g(x)=x^3-6x^2+9x+3 is 3x^2-12x+9

What is the first derivative of g(x)=x^3-6x^2+9x+3 ?

The first derivative of g(x)=x^3-6x^2+9x+3 is 3x^2-12x+9

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derivative of

g (x) = x^{3} - 6 x^{2} + 9 x + 3

3 x^{2} - 12 x + 9

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (3) = 0

= 3 x^{2} - 12 x + 9 + 0

Simplify

= 3 x^{2} - 12 x + 9

x = 4 - y^{2}, x = y^{2} - 4

\int \frac{p}{( p - 5 ) ^{2}} d p

\frac{d y}{d x} = 2 y + x^{2} + 9

\frac{d y}{d t} (t) = \frac{y}{25 t ^{2} + 1}

\int (t^{2} - 2) d t

What is the derivative of g(x)=x^3-6x^2+9x+3 ?
The derivative of g(x)=x^3-6x^2+9x+3 is 3x^2-12x+9
What is the first derivative of g(x)=x^3-6x^2+9x+3 ?
The first derivative of g(x)=x^3-6x^2+9x+3 is 3x^2-12x+9