What is the derivative of 3(8x^2-4x^4) ?

The derivative of 3(8x^2-4x^4) is 12(8x^2-4x)^3(16x-4)

What is the first derivative of 3(8x^2-4x^4) ?

The first derivative of 3(8x^2-4x^4) is 12(8x^2-4x)^3(16x-4)

Popular >

\frac{d}{d x} (3 (8 x^{2} - 4 x)^{4})

12 (8 x^{2} - 4 x)^{3} (16 x - 4)

Solution steps

\frac{d}{d x} (3 (8 x^{2} - 4 x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} ((8 x^{2} - 4 x)^{4})

Apply the chain rule:

4 (8 x^{2} - 4 x)^{3} \frac{d}{d x} (8 x^{2} - 4 x)

= 4 (8 x^{2} - 4 x)^{3} \frac{d}{d x} (8 x^{2} - 4 x)

\frac{d}{d x} (8 x^{2} - 4 x) = 16 x - 4

= 3 \cdot 4 (8 x^{2} - 4 x)^{3} (16 x - 4)

Simplify

= 12 (8 x^{2} - 4 x)^{3} (16 x - 4)

f (x) = 12 x^{2}

\int \frac{e ^{2 x} - 1}{e ^{x} + e ^{- x}} d x

x \to - 6 - lim (tan (\frac{π x}{4}))

\int e^{s i n (x)} sin (x) cos (x) d x

\int 6 x^{4} d x

What is the derivative of 3(8x^2-4x^4) ?
The derivative of 3(8x^2-4x^4) is 12(8x^2-4x)^3(16x-4)
What is the first derivative of 3(8x^2-4x^4) ?
The first derivative of 3(8x^2-4x^4) is 12(8x^2-4x)^3(16x-4)