What is the derivative of 1+3cos(2x) ?

The derivative of 1+3cos(2x) is -6sin(2x)

What is the first derivative of 1+3cos(2x) ?

The first derivative of 1+3cos(2x) is -6sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (1 + 3 cos (2 x))

- 6 sin (2 x)

Solution steps

\frac{d}{d x} (1 + 3 cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3 cos (2 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 cos (2 x)) = - 6 sin (2 x)

= 0 - 6 sin (2 x)

Simplify

= - 6 sin (2 x)

(ln (x^{2} - 1))^{^{'}}

y^{^{''}} - y^{^{'}} + 30 y = 0

3 sin (2 t) - 3 cos (2 t)

\frac{d}{d x} (x^{y} - y^{x})

y^{^{'}} - y = x^{2}

What is the derivative of 1+3cos(2x) ?
The derivative of 1+3cos(2x) is -6sin(2x)
What is the first derivative of 1+3cos(2x) ?
The first derivative of 1+3cos(2x) is -6sin(2x)