What is the derivative of f(x)=x^2-18x-4 ?

The derivative of f(x)=x^2-18x-4 is 2x-18

What is the first derivative of f(x)=x^2-18x-4 ?

The first derivative of f(x)=x^2-18x-4 is 2x-18

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derivative of

f (x) = x^{2} - 18 x - 4

2 x - 18

Solution steps

\frac{d}{d x} (x^{2} - 18 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (18 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (18 x) = 18

\frac{d}{d x} (4) = 0

= 2 x - 18 - 0

Simplify

= 2 x - 18

\int (2 x - x - \frac{9}{x ^{2}}) d x

y^{^{''}} - 4 y^{^{'}} + 4 y = t^{3} e^{2 t}, y (0) = 0, y^{^{'}} (0) = 0

f (x) = cot (x)

\frac{d ^{2}}{d x ^{2}} (e^{2 x})

(x^{2} y + y) y^{^{'}} = 2 x y^{2} + 6 x

What is the derivative of f(x)=x^2-18x-4 ?
The derivative of f(x)=x^2-18x-4 is 2x-18
What is the first derivative of f(x)=x^2-18x-4 ?
The first derivative of f(x)=x^2-18x-4 is 2x-18