What is the derivative of 8^x-5^x ?

The derivative of 8^x-5^x is 3ln(2)*8^x-5^xln(5)

What is the first derivative of 8^x-5^x ?

The first derivative of 8^x-5^x is 3ln(2)*8^x-5^xln(5)

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\frac{d}{d x} (8^{x} - 5^{x})

3 ln (2) \cdot 8^{x} - 5^{x} ln (5)

Solution steps

\frac{d}{d x} (8^{x} - 5^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8^{x}) - \frac{d}{d x} (5^{x})

\frac{d}{d x} (8^{x}) = 3 ln (2) \cdot 8^{x}

\frac{d}{d x} (5^{x}) = 5^{x} ln (5)

= 3 ln (2) \cdot 8^{x} - 5^{x} ln (5)

x \to 0 + lim ((4 x)^{\frac{4}{x}})

(- 8, 8), (1, - 10)

\frac{d}{d x} ((x + 3) I n x^{2})

\int (7 x - 6)^{4} d x

\int \frac{1}{y ^{2} + 2 y} d y

What is the derivative of 8^x-5^x ?
The derivative of 8^x-5^x is 3ln(2)*8^x-5^xln(5)
What is the first derivative of 8^x-5^x ?
The first derivative of 8^x-5^x is 3ln(2)*8^x-5^xln(5)