What is (\partial)/(\partial x)((3x^2+5x+1)(y+4)) ?

The answer to (\partial)/(\partial x)((3x^2+5x+1)(y+4)) is (y+4)(6x+5)

Popular >

(\partial)/(\partial x)((3x^2+5x+1)(y+4))

\frac{\partial}{\partial x} ((3 x^{2} + 5 x + 1) (y + 4))

(y + 4) (6 x + 5)

Solution steps

\frac{\partial}{\partial x} ((3 x^{2} + 5 x + 1) (y + 4))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y + 4) \frac{\partial}{\partial x} (3 x^{2} + 5 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (y + 4) (\frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (5 x) + \frac{\partial}{\partial x} (1))

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (5 x) = 5

\frac{\partial}{\partial x} (1) = 0

= (y + 4) (6 x + 5 + 0)

Simplify

= (y + 4) (6 x + 5)

y = (x - 5) (x + 4) (x + 6)

\int \frac{1}{x cos ^{2} ( ln ( x ) )} d x

\int (5 + e^{3 x^{2}}) x d x

\frac{1}{t ^{2} + 5 t - 4}

\frac{d}{d x} (3 x^{\frac{5}{3}} + 4 x^{- \frac{2}{3}} - 7 x^{\frac{3}{4}})

What is (\partial)/(\partial x)((3x^2+5x+1)(y+4)) ?
The answer to (\partial)/(\partial x)((3x^2+5x+1)(y+4)) is (y+4)(6x+5)