What is the limit as x approaches 0 of-x^2ln(6x^3) ?

The limit as x approaches 0 of-x^2ln(6x^3) is Does not exist

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limit as x approaches 0 of-x^2ln(6x^3)

x \to 0 lim (- x^{2} ln (6 x^{3}))

Does not exist

Solution steps

x \to 0 lim (- x^{2} ln (6 x^{3}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (- x^{2} ln (6 x^{3})) = 0

x \to 0 - lim (- x^{2} ln (6 x^{3})) =

Does not exist

= Does not exist

g (x) = 2 x^{2} + 8 x - 3, at x = - 3

\int \frac{1}{3 - 2 cos ( x )} d x

\int_{1}^{16} \frac{1}{6 - x} d x

\int \frac{x ^{3} + x ^{2} - x - 3}{x ^{2} - 3} d x

\frac{cot ( t )}{e ^{t}}

What is the limit as x approaches 0 of-x^2ln(6x^3) ?
The limit as x approaches 0 of-x^2ln(6x^3) is Does not exist