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Popular >

y^'=y(5-y)

Solution

y^{^{'}} = y (5 - y)

Solution

y = \frac{5}{- e ^{- 5 t - c_{1}} + 1}

Solution steps

y^{'} (t) = y (5 - y)

Solve Bernoulli ODE:

y = \frac{5}{- e ^{- 5 t - c_{1}} + 1}

y = \frac{5}{- e ^{- 5 t - c_{1}} + 1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=y(5-y) ?
The solution for y^'=y(5-y) is y= 5/(-e^{-5t-c_{1)}+1}