What is the limit as x approaches 0 of-x/(1+x^2) ?

The limit as x approaches 0 of-x/(1+x^2) is 0

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limit as x approaches 0 of-x/(1+x^2)

x \to 0 lim (- \frac{x}{1 + x ^{2}})

0

Solution steps

x \to 0 lim (- \frac{x}{1 + x ^{2}})

Plug in the value

x = 0

= - \frac{0}{1 + 0 ^{2}}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

\int \frac{4 + x ^{2}}{x ^{6}} d x

\int \frac{x}{( x - 1 ) ( x - 2 )} d x

\int y arctan (2 y) d y

6 y^{^{''}} + y = 0

y^{^{'}} - \frac{6}{x} y = \frac{y ^{3}}{x ^{9}}

What is the limit as x approaches 0 of-x/(1+x^2) ?
The limit as x approaches 0 of-x/(1+x^2) is 0