What is the solution for y^{''}+(10+5)y=((10-5))/2 ?

The solution for y^{''}+(10+5)y=((10-5))/2 is y=c_{1}cos(sqrt(15)t)+c_{2}sin(sqrt(15)t)+1/6

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y^{''}+(10+5)y=((10-5))/2

y^{^{''}} + (10 + 5) y = \frac{( 10 - 5 )}{2}

y = c_{1} cos (15 t) + c_{2} sin (15 t) + \frac{1}{6}

Solution steps

y^{''} (t) + (10 + 5) y = \frac{( 10 - 5 )}{2}

Solve linear ODE:

y = c_{1} cos (15 t) + c_{2} sin (15 t) + \frac{1}{6}

y = c_{1} cos (15 t) + c_{2} sin (15 t) + \frac{1}{6}

\frac{( x + x ^{2} + 8 )}{2}

x \cdot sin (x) + x \cdot cos (x)

\int 2 x^{- 1} d x

{\frac{1}{s ^{2}} - \frac{1}{s} + \frac{1}{s - 2}}

\int (\frac{y}{x} + 6 x) d x

What is the solution for y^{''}+(10+5)y=((10-5))/2 ?
The solution for y^{''}+(10+5)y=((10-5))/2 is y=c_{1}cos(sqrt(15)t)+c_{2}sin(sqrt(15)t)+1/6