What is the derivative of 1/x-3sin(x) ?

The derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)

What is the first derivative of 1/x-3sin(x) ?

The first derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{1}{x} - 3 sin (x))

- \frac{1}{x ^{2}} - 3 cos (x)

Solution steps

\frac{d}{d x} (\frac{1}{x} - 3 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (3 sin (x))

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

= - \frac{1}{x ^{2}} - 3 cos (x)

\int 3 x + 5 d x

\int (\frac{2}{x ^{2}} + sec (x) tan (x)) d x

\int \frac{13 x ^{3}}{3 + x ^{2}} d x

\int sin^{5} (x co) s^{2} x d x

\int \frac{4}{6 - 2 x} d x

What is the derivative of 1/x-3sin(x) ?
The derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)
What is the first derivative of 1/x-3sin(x) ?
The first derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)