What is the integral of (x^2+sec^2(x)) ?

The integral of (x^2+sec^2(x)) is (x^3)/3+tan(x)+C

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integral of (x^2+sec^2(x))

\int (x^{2} + sec^{2} (x)) d x

\frac{x ^{3}}{3} + tan (x) + C

Solution steps

\int x^{2} + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int sec^{2} (x) d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int sec^{2} (x) d x = tan (x)

= \frac{x ^{3}}{3} + tan (x)

Add a constant to the solution

= \frac{x ^{3}}{3} + tan (x) + C

n = 0 \sum \infty 0.7 4^{n}

x \to 3 lim (\frac{2 + x}{3 - x})

\int \frac{1}{x ln ( 3 x )} d x

\int \frac{5 + x}{5 - x} d x

\frac{\partial}{\partial x} (x^{3} e^{2 x y})

What is the integral of (x^2+sec^2(x)) ?
The integral of (x^2+sec^2(x)) is (x^3)/3+tan(x)+C