What is the derivative of 2pir^2 ?

The derivative of 2pir^2 is 4pir

What is the first derivative of 2pir^2 ?

The first derivative of 2pir^2 is 4pir

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derivative of

2 π r^{2}

4 π r

Solution steps

\frac{d}{d r} (2 π r^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 π \frac{d}{d r} (r^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 π 2 r^{2 - 1}

Simplify

= 4 π r

y = (x - 2)^{4 x}

\int \frac{x ^{3} + 3 x ^{2} - 2 x + 1}{x ^{4} + 5 x ^{2} + 4} d x

\frac{d}{d x} \frac{( x ^{2} - 1 ) ^{\frac{3}{2}}}{3 x ^{3}}

x \to 9 + lim (\frac{2}{x - 9})

f (x) = \frac{20 x}{x ^{2} - 5}, (5, 5)