What is the derivative of 4e^{3x} ?

The derivative of 4e^{3x} is 12e^{3x}

What is the first derivative of 4e^{3x} ?

The first derivative of 4e^{3x} is 12e^{3x}

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\frac{d}{d x} (4 e^{3 x})

12 e^{3 x}

Solution steps

\frac{d}{d x} (4 e^{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (e^{3 x})

Apply the chain rule:

e^{3 x} \frac{d}{d x} (3 x)

= e^{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 4 e^{3 x} \cdot 3

Simplify

= 12 e^{3 x}

f (x) = (x^{3} + 2 x - 2)^{4}

3 e^{3 x} \frac{d y}{d x} = - 9 \frac{x}{y ^{2}}

x \to \frac{π}{2} lim (7 sec (x) - 7 tan (x))

\frac{d}{d x} (arctan (\frac{x - 1}{x + 1}))

\int_{0}^{x} e^{- x} d x

What is the derivative of 4e^{3x} ?
The derivative of 4e^{3x} is 12e^{3x}
What is the first derivative of 4e^{3x} ?
The first derivative of 4e^{3x} is 12e^{3x}