What is the derivative of x^2s^4+y^5s+z^3 ?

The derivative of x^2s^4+y^5s+z^3 is 2xs^4

What is the first derivative of x^2s^4+y^5s+z^3 ?

The first derivative of x^2s^4+y^5s+z^3 is 2xs^4

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derivative of

x^{2} s^{4} + y^{5} s + z^{3}

2 x s^{4}

Solution steps

\frac{d}{d x} (x^{2} s^{4} + y^{5} s + z^{3})

Treat

s, y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} s^{4}) + \frac{d}{d x} (y^{5} s) + \frac{d}{d x} (z^{3})

\frac{d}{d x} (x^{2} s^{4}) = 2 s^{4} x

\frac{d}{d x} (y^{5} s) = 0

\frac{d}{d x} (z^{3}) = 0

= 2 s^{4} x + 0 + 0

Simplify

= 2 x s^{4}

\int (\frac{5}{x} + 5 x) d x

2 x y^{^{'}} - 10 y = x^{- 2}

n \to \infty lim (n (n + 1))

\int (\frac{cy}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}) d y

\int sin (4 x) d x

What is the derivative of x^2s^4+y^5s+z^3 ?
The derivative of x^2s^4+y^5s+z^3 is 2xs^4
What is the first derivative of x^2s^4+y^5s+z^3 ?
The first derivative of x^2s^4+y^5s+z^3 is 2xs^4