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Popular >

y^'-y=1,y(0)=0

Solution

y^{^{'}} - y = 1, y (0) = 0

Solution

y = e^{t} - 1

Solution steps

y^{'} (t) - y = 1

Solve separable ODE:

y = e^{t} - 1

y = e^{t} - 1

Graph

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(x e^{2 x})^{^{'}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'-y=1,y(0)=0 ?
The solution for y^'-y=1,y(0)=0 is y=e^t-1