What is the limit as x approaches 1 of 5/(x^2-1) ?

The limit as x approaches 1 of 5/(x^2-1) is diverges

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limit as x approaches 1 of 5/(x^2-1)

x \to 1 lim (\frac{5}{x ^{2} - 1})

diverges

Solution steps

x \to 1 lim (\frac{5}{x ^{2} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{5}{x ^{2} - 1}) = \infty

x \to 1 - lim (\frac{5}{x ^{2} - 1}) = - \infty

= diverges

\frac{d}{d x} (\frac{x ^{3}}{e ^{\frac{1}{x}}})

f (x) 6 - 7 x + 5 x^{2}

x \to \infty lim (8 x + 1)

x \to - 1 lim (\frac{x ^{3} - 1}{x + 1})

\int x^{11} x^{6} + 3 d x

What is the limit as x approaches 1 of 5/(x^2-1) ?
The limit as x approaches 1 of 5/(x^2-1) is diverges