What is the derivative of 1/(2sqrt(r))+1/(5r^{4/5)} ?

The derivative of 1/(2sqrt(r))+1/(5r^{4/5)} is -1/(4r^{3/2)}-4/(25r^{9/5)}

What is the first derivative of 1/(2sqrt(r))+1/(5r^{4/5)} ?

The first derivative of 1/(2sqrt(r))+1/(5r^{4/5)} is -1/(4r^{3/2)}-4/(25r^{9/5)}

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derivative of

\frac{1}{2 r} + \frac{1}{5 r ^{\frac{4}{5}}}

- \frac{1}{4 r ^{\frac{3}{2}}} - \frac{4}{25 r ^{\frac{9}{5}}}

Solution steps

\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{5 r ^{\frac{4}{5}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (\frac{1}{2 r}) + \frac{d}{d r} (\frac{1}{5 r ^{\frac{4}{5}}})

\frac{d}{d r} (\frac{1}{2 r}) = - \frac{1}{4 r ^{\frac{3}{2}}}

\frac{d}{d r} (\frac{1}{5 r ^{\frac{4}{5}}}) = - \frac{4}{25 r ^{\frac{9}{5}}}

= - \frac{1}{4 r ^{\frac{3}{2}}} - \frac{4}{25 r ^{\frac{9}{5}}}

\int \frac{- x}{1 - 0.5 x} d x

\frac{\partial}{\partial x} (2 x^{2} - 4 x y + y^{4})

\frac{d}{d x} (2 x - x + 3)

sin^{2} (x^{2})

x \to \frac{1}{2} lim (∣ x ∣)

What is the derivative of 1/(2sqrt(r))+1/(5r^{4/5)} ?
The derivative of 1/(2sqrt(r))+1/(5r^{4/5)} is -1/(4r^{3/2)}-4/(25r^{9/5)}
What is the first derivative of 1/(2sqrt(r))+1/(5r^{4/5)} ?
The first derivative of 1/(2sqrt(r))+1/(5r^{4/5)} is -1/(4r^{3/2)}-4/(25r^{9/5)}