What is the tangent of f(x)=x^2-2,\at x=a ?

The tangent of f(x)=x^2-2,\at x=a is y=2ax-a^2-2

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tangent of f(x)=x^2-2,\at x=a

tangent of

f (x) = x^{2} - 2, at x = a

y = 2 a x - a^{2} - 2

Solution steps

Find the tangent point:

(a, a^{2} - 2)

Find the slope of

f (x) = x^{2} - 2 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 a

Find the line with slope m=

2 a

and passing through

(a, a^{2} - 2) : y = 2 a x - a^{2} - 2

y = 2 a x - a^{2} - 2

\int x^{2} sin (2 x) x d x

\int \frac{x + 1}{x ^{2} + 7 x + 10} d x

\int 12 - 8 x + x^{2} d x

\frac{d ^{2} S}{d x ^{2}} = S

x \to - \infty lim (- 3 x^{3} - x)

What is the tangent of f(x)=x^2-2,\at x=a ?
The tangent of f(x)=x^2-2,\at x=a is y=2ax-a^2-2