What is (\partial)/(\partial z)(x^2+xy+y^2+2x-y) ?

The answer to (\partial)/(\partial z)(x^2+xy+y^2+2x-y) is 0

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(\partial)/(\partial z)(x^2+xy+y^2+2x-y)

\frac{\partial}{\partial z} (x^{2} + x y + y^{2} + 2 x - y)

0

Solution steps

\frac{\partial}{\partial z} (x^{2} + x y + y^{2} + 2 x - y)

Treat

x, y

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} (x ln (a))

\frac{d}{d x} (22 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

\int (2 sin (x) - 3 cos (x) + 12) d x

\frac{\partial}{\partial x} (x - 4 y)

(1 + x^{- 1})^{2}

What is (\partial)/(\partial z)(x^2+xy+y^2+2x-y) ?
The answer to (\partial)/(\partial z)(x^2+xy+y^2+2x-y) is 0