What is (\partial)/(\partial x)(8e^{x-y}) ?

The answer to (\partial)/(\partial x)(8e^{x-y}) is 8e^{x-y}

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(\partial)/(\partial x)(8e^{x-y})

\frac{\partial}{\partial x} (8 e^{x - y})

8 e^{x - y}

Solution steps

\frac{\partial}{\partial x} (8 e^{x - y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{\partial}{\partial x} (e^{x - y})

Apply the chain rule:

e^{x - y} \frac{\partial}{\partial x} (x - y)

= e^{x - y} \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= 8 e^{x - y} \cdot 1

Simplify

= 8 e^{x - y}

\int 2 - x - x^{2} d x

\frac{\partial}{\partial x} (e^{x^{2} + y})

\int 5 sin^{3} (x co) s^{2} x d x

\frac{d y}{d x} = \frac{y}{x} + csc (\frac{y}{x})

- 2 sin (x^{2}) - 4 x^{2} cos (x^{2})

What is (\partial)/(\partial x)(8e^{x-y}) ?
The answer to (\partial)/(\partial x)(8e^{x-y}) is 8e^{x-y}