What is area y= 5/x ,y= 5/(x^2),x=4 ?

The answer to area y= 5/x ,y= 5/(x^2),x=4 is 10ln(2)-15/4

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area y= 5/x ,y= 5/(x^2),x=4

area

y = \frac{5}{x}, y = \frac{5}{x ^{2}}, x = 4

10 ln (2) - \frac{15}{4}

Decimal

3.18147 \dots

Solution steps

Apply the area formula:

\int_{1}^{4} \frac{5}{x} - \frac{5}{x ^{2}} d x

Solve

\int_{1}^{4} \frac{5}{x} - \frac{5}{x ^{2}} d x : 10 ln (2) - \frac{15}{4}

The area is:

= 10 ln (2) - \frac{15}{4}

\frac{10 3 z}{z ^{2}}

\frac{d}{d x} (A e^{3 x} \cdot 3)

\frac{s - 3}{s ^{2} + 4 s + 13}

\frac{[ y - y ^{2} ]}{t} = y^{^{'}}, y (1) = 2

x \to 0 lim (x (11 + \frac{4}{x}))

What is area y= 5/x ,y= 5/(x^2),x=4 ?
The answer to area y= 5/x ,y= 5/(x^2),x=4 is 10ln(2)-15/4