What is the integral of (sec^2(x)tan(x)) ?

The integral of (sec^2(x)tan(x)) is (tan^2(x))/2+C

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integral of (sec^2(x)tan(x))

\int (sec^{2} (x) tan (x)) d x

\frac{tan ^{2} ( x )}{2} + C

Solution steps

\int sec^{2} (x) tan (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = tan (x)

= \frac{tan ^{2} ( x )}{2}

Add a constant to the solution

= \frac{tan ^{2} ( x )}{2} + C

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y = x + e^{2 x}

What is the integral of (sec^2(x)tan(x)) ?
The integral of (sec^2(x)tan(x)) is (tan^2(x))/2+C