What is the integral from-4 to 4 of x(16-x^2) ?

The integral from-4 to 4 of x(16-x^2) is 0

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integral from-4 to 4 of x(16-x^2)

\int_{- 4}^{4} x (16 - x^{2}) d x

0

Solution steps

\int_{- 4}^{4} x (16 - x^{2}) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x (16 - x^{2}) :

Odd

= 0

x \to 6 lim (5 x + 6)

\frac{d}{d x} (e^{x - 1} - ln (x) - (x - 1)^{2} - 1)

\int_{1}^{2} 5 4 x^{2} - 3 d x

(\frac{1}{t - 1})^{^{'}}

\int \frac{x}{( 7 x ^{2} + 3 ) ^{5}} d x

What is the integral from-4 to 4 of x(16-x^2) ?
The integral from-4 to 4 of x(16-x^2) is 0